SOLUTION: Juice-O-Rama is a refreshment stand specializing in a fruit drink mixture of orange juice and prune juice. The orange juice costs $1.20 per liter and the prune juice costs $1.40 pe

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Question 622586: Juice-O-Rama is a refreshment stand specializing in a fruit drink mixture of orange juice and prune juice. The orange juice costs $1.20 per liter and the prune juice costs $1.40 per liter. If they need 8 liters of the final drink at a cost of $1.24 per liter, how many liters of each juice will they need to make their specialty drink?
This is the work i've done, i need help.
x=the number of liters of orange juice
y=the number of liters of prune juice
x+y=8
1.20x+1.40y=1.24
20(8-y)+1.40y=1.24
1.20(9.4)=1.24

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Note that +1.2x+%2B+1.4y+ is the total cost of
the o.j. and p.j. used.
So you need to divide this by total liters needed
to get the cost/liter
(1) +%28+1.2x+%2B+1.4y+%29+%2F+8+=+1.24+
and the other equation is:
(2) +x+%2B+y+=+8+
----------------
(1) +1.2x+%2B+1.4y+=+1.24%2A8+
(1) +1.2x+%2B+1.4y+=+9.92+
(1) +120x+%2B+140y+=+992+
Multiply both sides of (2) by +120+
and subtract (2) from (1)
(1) +120x+%2B+140y+=+992+
(2) +-120x+-+120y+=+-960+
+20y+=+32+
+y+=+1.6+
and, since
(2) +x+%2B+y+=+8+
(2) +x+%2B+1.6+=+8+
(2) +x+=+6.4+
6.4 liters of OJ and 1.6 liters of PJ are needed
-------------
check answer:
(1) +%28+1.2x+%2B+1.4y+%29+%2F+8+=+1.24+
(1) +%28+1.2%2A6.4+%2B+1.4%2A1.6+%29+%2F+8+=+1.24+
(1) +%28+7.68+%2B+2.24+%29+%2F+8+=+1.24+
(1) +9.92+%2F+8+=+1.24+
(1) +9.92+=+9.92+
OK