Question 62253: Instructions: Perform the indicated operations.
What is the solution for (2x+3y)^3 Found 2 solutions by stanbon, funmath:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! (2x+3y)^3
The form is (a+b)^3=a^3+3a^2b+3ab^2+b^3
In your case a=2x and b=3y so you get:
(2x)^3+3(2x)^2(3y)+3(2x)(3y)^2+(3y)^3
=8x^3+36x^2y+54xy^2+27y^3
Cheers,
Stan H.
You can put this solution on YOUR website! (2x+3y)^3
(2x+3y)(2x+3y)(2x+3y) Work the last two parentheses first.
(2x+3y)[2x(2x+3y)+3y(2x+3y)]
(2x+3y)[2x(2x)+2x(3y)+3y(2x)+3y(3y)]
Now distribute the first term in the first parentheses through the second parentheses, then the second term in the first parentheses into the second parentheses.
Happy Calculating!!!
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