SOLUTION: A Piece of wire 76 cm long is cut into two pieces, each bent to make a square. The of a side of one square is to be 3cm longer than the length of a side of the other. How should th

Algebra ->  Customizable Word Problem Solvers  -> Geometry -> SOLUTION: A Piece of wire 76 cm long is cut into two pieces, each bent to make a square. The of a side of one square is to be 3cm longer than the length of a side of the other. How should th      Log On

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Question 622433: A Piece of wire 76 cm long is cut into two pieces, each bent to make a square. The of a side of one square is to be 3cm longer than the length of a side of the other. How should the wire be cut?
Answer by matineesuxxx(27) About Me  (Show Source):
You can put this solution on YOUR website!
so the side of one square will be x and the length of the other square is going to be x+3,
now we know the total perimeter is going to add up to 76cm, and the formula for perimeter of a square is P=4L
so for total perimeter is going to be the perimeter of the two squares ass, hence,
Tp=4x%2B4%28x%2B3%29
76=8x%2B12
64=8x
x=8