SOLUTION: I need help with these 4 problems I need to graph the following x = 3y - 6 2x - y = -2 y = 2/3x + 4 y = 2 Thank you for your help.

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Question 622367: I need help with these 4 problems
I need to graph the following
x = 3y - 6
2x - y = -2
y = 2/3x + 4
y = 2
Thank you for your help.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
I need help with these 4 problems
I need to graph the following
x = 3y - 6
2x - y = -2
y+=+%282%2F3%29x+%2B+4
y = 2
Thank you for your help.

1) Solve each equation for y, or put in y = mx + b form
x = 3y - 6

x + 6 = 3y

y+=+%281%2F3%29x+%2B+2

Because the graph of the equation will intersect the y-axis at x = 0, and the y-intercept (b) is 2, then the graph will intersect the y-axis at coordinate point, (0, 2)

Because the graph of the equation will intersect the x-axis at y = 0, we set the y-value in the equation at 0 (zero) to get:

0+=+%281%2F3%29x+%2B+2

%281%2F3%29x+=+-+2 ---- Isolating the variable

x+=+%28-+2%29%2F%281%2F3%29

x = - 2 * 3, or - 6, which gives us an x-intercept coordinate point of (- 6, 0)

Now just join the points, (0, 2) and (- 6, 0), and you have your graph

I'm sure you can do the others by applying the same concept.

N.B.
Number 3 has already been solved for y, or is already in y = mx + b form
Number 4 is a horizontal line at y = 4. That's all it takes to graph this one.

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