SOLUTION: I have to solve this algebraically, not by using a graph: A parabola has a vertex (8, 3) and one x intercept of 5. Determine the coordinates of the other x- intercept.

Algebra ->  Functions -> SOLUTION: I have to solve this algebraically, not by using a graph: A parabola has a vertex (8, 3) and one x intercept of 5. Determine the coordinates of the other x- intercept.       Log On


   

Question 622355: I have to solve this algebraically, not by using a graph: A parabola has a vertex (8, 3) and one x intercept of 5. Determine the coordinates of the other x- intercept.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

solving algebraically:  Parabola with V(8,3) and passing thru (5,0) 

 y = a(x -8)^2 + 3

 0 = a(5-8)^2 + 3

 -3/9 = a

 y = (-1/3)(x-8)^2 + 3

 0 = (-1/3)(x-8)^2 + 3

      -3 = (-1/3)(x-8)^2

       (x-8)^2 = 9

        (x-8) = ± 3

          x = 5 and x = 11 

    (11,0) are the coordinates of the other x- intercept.