Question 622310: (Sin)sqx+(cos)sqx=1? Why
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! (Sin)sqx+(cos)sqx=1? Why
Let me try using a right triangle
let o=opposite side
let a=adjacent side
let h=hypotenuse
..
sin=o/h
cos=a/h
sin^2=o^2/h^2
cos^2=a^2/h^2
sin^2+cos^2
=o^2/h^2+a^2/h^2
=(o^2+a^2)/h^2
=1
By Pythagorean Theorem:
The sum of the squares of the two sides=the square of the hypotenuse.
Therefore, (o^2+a^2)/h^2=1
|
|
|
