SOLUTION: Find all values of θ, if θ is in the interval [0°, 360°) and has the following function value sinθ = - sqrt3/2

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Question 622255: Find all values of θ, if θ is in the interval [0°, 360°) and has the following function value sinθ = - sqrt3/2
Answer by lwsshak3(11628) About Me  (Show Source):
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Find all values of θ, if θ is in the interval [0°, 360°) and has the following function value sinθ = - sqrt3/2
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sinθ = -√3/2 in quadrants III and IV where sin<0
reference angle=60º
θ=240º and 300º