SOLUTION: I am lost on this one Graph Y=3x^2-8x+2 and give the vertex, dpmai and range? Thank you for your help

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Question 62196: I am lost on this one
Graph Y=3x^2-8x+2 and give the vertex, dpmai and range?
Thank you for your help

Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
Graph Y=3x^2-8x+2 and give the vertex, domain and range?
The y-intercept happens when x=0
y=3(0)^2-8(0)+2
y=0-0+2
y=2 Plot (0,2)
:
The quadratic equation is in standard form y=ax%5E2%2Bbx%2Bc
a=3, b=-8, and c=2
Because a is positive, the parabola opens upward.
The x coordinate of the vertex is found with the formula x=-b%2F2a
x=-%28-8%29%2F%282%283%29%29
x=8%2F6
x=4%2F3
Substitute that into the equation to find the y coordinate.
y=3%284%2F3%29%5E2-8%284%2F3%29%2B2
y=3%2816%2F9%29-32%2F3%2B2
y=16%2F3-32%2F3%2B2
y=16%2F3-32%2F3%2B6%2F3
y=-10%2F3
The vertex is (4/3,-10/3)
The domain for all parabolas is all real numbers. {x|x=R}
The range is from the vertex upward since it opens upward. {y|y>=-10/3}
graph%28300%2C200%2C-10%2C10%2C-10%2C10%2C3x%5E2-8x%2B2%29
Happy Calculating!!!