SOLUTION: Can you help me solve these equations using the substitution method?
1) x-y=15; y=-4x
2) 5x+3y=0 ;x+y=0
Can you help me solve these equations using the el
Algebra ->
Linear-equations
-> SOLUTION: Can you help me solve these equations using the substitution method?
1) x-y=15; y=-4x
2) 5x+3y=0 ;x+y=0
Can you help me solve these equations using the el
Log On
You can put this solution on YOUR website! Can you help me solve these equations using the substitution method?
1) x - y = 15; y = -4x
:
Notice they show y = -4x, therefore we can substitute -4x for y in the 1st
equation and solve for x:
x - (-4x) = 15; minus a minus is a plus:
x + 4x = 15
5x = 15
:
x = 15/5, divided both sides by 5
x = 3
:
Find y by substituting 3 for x:
y = -4x
y = -4(3)
y = -12
:
Check our solutions by substituting 3 for x and -12 for y in the 1st equation:
x - y = 15
3 - (-12) = 15
3 + 12 = 15 proves our solutions
:
:
:
2) 5x+3y=0 ;x+y=0
Take the 2nd equation are arrange it in the y = form:
x + y = 0
y = -x, subtracted x from both sides:
:
Substitute -x for y in the 1st equation:
5x + 3y = 0
5x + 3(-x) = 0
5x - 3x = 0
Obviously the only value where this could be true is that x = 0 then y = 0 also
:
:
Can you help me solve these equations using the elimination method?
In this you arrange the equations in a manner where if they are added or subtracted, one of the unknowns is eliminated,
1)
a + b = 4
-a + 2b = -8
------------------adding eliminates a:
0 + 3b = -4
b = -4/3
: Find a, substitute -4/3 for b in the 1st equation:
a + b = 4
a +(-4/3) = 4
a - (4/3) = 4
a = 4 + (4/3); added (4/3) to both sides:
a = (12/3) + (4/3); add using common denominator
a = 16/3
:
Check: substitute (-4/3) for b and (16/3) for a in the 2nd equation:
-a + 3b = -8
-(16/3) + 2(-4/3) = -8
-(16/3) - (8/3) = (-24/3) which = -8
:
:
:
2)
x + 4y = -3
4x + y = -9
Mult the 1st equation by 4, leave the 2nd equation as it is:
4x + 16y = -12
4x + y = -9
---------------------Subtracting eliminates x:
0x + 15y = -3
y = -3/15
y = -1/5 or -.2
:
Find x: Substitute =.2 for y in the 1st equation
x + 4y = -3
x + 4(-.2) = -3
x - .8 = -3
x = -3 + .8
x = -2.2
:
Check our solution in the 2nd equation:
4x + y = -9
4(-2.2) + (-.2) = -9
-8.8 - .2 = -9 checks out our solutions:
:
:
3)
8x + 2y = 3
x - 7y = 19
:
Mult the 2nd equation by 8:
8x + 2y = 3
8x -56y = 152
--------------Subtracting eliminates x:
0x + 58y = - 149
y = -149/58; a nasty fraction
:
Find x using the 1st equation
8x + 2y = 3
8x +2(-149/58) = 3
8x - 298/58 = 3
Get rid of the denominator, mult eq by 58:
464x - 298 = 174
464x = 174 + 298
464x = 472
x = 472/464
x = 59/58
:
Check using the 2nd equation
x - 7y = 19
(59/58) - 7(-149/58) = 19
(59/58) + 1043/58 = 19 = 19
1102/58 = 19
19 = 19, proves these nasty fractions are indeed the solutions!