SOLUTION: When Fritz drives to work his trip takes 36 minutes, but when he takes the train it takes 20 minutes. Find the distance Fritz travels to work if the train travels an average of 48

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Question 621503: When Fritz drives to work his trip takes 36 minutes, but when he takes the train it takes 20 minutes. Find the distance Fritz travels to work if the train travels an average of 48 miles per hour faster than his driving.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
When Fritz drives to work his trip takes 36 minutes, but when he takes the train it takes 20 minutes.
Find the distance Fritz travels to work if the train travels an average of 48 miles per hour faster than his driving.
:
Change 20 min to 1%2F3 hrs
Change 36 min to 3%2F5 hrs
:
Find his speed first
Let s = car speed
then
(s+48) = train speed
:
Write a distance equation; dist = time * speed
1%2F3(s+48) = 3%2F5s
multiply both sides by 15 to get rid of the denominators; results
5(s+48) = 3(3s)
5s + 240 = 9s
240 = 9s - 5s
240 = 4s
s = 240/4
s = 60 mph in the car
Find the distance
3%2F5* 60 = 36 mi
:
Check the distance using the train (60+48) = 108 mi mph
1%2F3* 108 = 36 mi also, confirms our solution of 36 mi