SOLUTION: Find three consecutive intergers whose sum is 63.

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Question 62131: Find three consecutive intergers whose sum is 63.
Found 2 solutions by joyofmath, stanbon:
Answer by joyofmath(189) About Me  (Show Source):
You can put this solution on YOUR website!
Find three consecutive intergers whose sum is 63.
x + x+1 + x+2 = 63
3x+3 = 63
3x=60
x=20
So, the numbers are 20, 21, and 22.
Verify:
20+21+22 = 63

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
x+(x+1)+(x+2)=63
3x+3=63
3x=60
x=20
x+1=21
x+2=22
Cheers,
Stan H.