SOLUTION: Using complete sentences, explain how to factor each one. Be sure that the final factorization (or "answer") is a part of your explanation. 10x2 − 7x − 3

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Question 620914: Using complete sentences, explain how to factor each one. Be sure that the final factorization (or "answer") is a part of your explanation.
10x2 − 7x − 3

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
This is how I do it.
To factor the quadratic trinomial 10x%5E2-7x-3 ,
I first multiply together the absolute values of the leading coefficient (10) and the independent term (-3) to get 10%2A3=30.
I look for, and list all pairs of factors that multiply to yield that product, and find 4 such pairs:
1%2A30=30
2%2A15=30
3%2A10=30
5%2A6=30.
One of those pairs will be the absolute values of the coefficients of first degree terms obtained when multiplying the final factorization.
Because the independent term (-3) is negative, I know that those coefficients of first degree terms have opposite signs.
I also know that they add up to the coefficient of the first degree term in the original polynomial (-7).
From the four pairs of factors found above, the pair of factors, with signs, that add up to -7 is
-10%2B3=-7.
The expanded product of the factorization will contain -10x and %2B3x in addition to the leading and independent terms 10x%5E2 and -3.
I then organize the expanded product of the factorization in a 2 by 2 square, with the newly found terms at opposite corners:

Next, I look for common factors for each row and column and write them on the same row/column, outside the square.
I find 10x as a common factor for 10x%5E2 and -10x, so I write 10x to the left of 10x%5E2.
I find 3 as a common factor for 3x and -3, so I write 3 to the left of 3x.
I write x above 10x%5E2 and -10x, because it is their common factor.
I write -1 above -10x and -3, because it is their common factor.

Now I make a binomial of the terms written above the square x-1 and another binomial with the terms written to the left of the square 10x%2B3.
I multiply those binomials to verify that the terms inside the square are generated.
I also verify that collecting terms in that product produces the original trinomial.
%2810x%2B3%29%28x-1%29=10x%5E2-10x%2B3x-3=10x%5E2-7x-3