SOLUTION: proove that log2 + 16log16/15 + 12log25/24 + 7log81/80 = 1

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Question 620714: proove that log2 + 16log16/15 + 12log25/24 + 7log81/80 = 1
Answer by lwsshak3(11628) About Me  (Show Source):
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proove that log2 + 16log16/15 + 12log25/24 + 7log81/80 = 1
log[2*(16/15)^16*(25/24)^12*(81/80)^7]=log[10]
log[10]=1