SOLUTION: I have no idea how to work this problem, could someone help me? In an amplifier, the power gain P is given by the function: P= 10 log Pout/Pin where Pin is the power input i

Algebra ->  Functions -> SOLUTION: I have no idea how to work this problem, could someone help me? In an amplifier, the power gain P is given by the function: P= 10 log Pout/Pin where Pin is the power input i      Log On


   



Question 62064: I have no idea how to work this problem, could someone help me?
In an amplifier, the power gain P is given by the function:
P= 10 log Pout/Pin
where Pin is the power input in watts and Pout is the power output in watts. If an amplififier has a power gain of 10 watts and the output power is 7 watts, find the input power.
(added note the out and in words next to the P are suppose to be lower than the P, but I don't know how to show it on here. so it would be the opposite of using the ^ sign to do what I mean.)

Found 2 solutions by Nate, stanbon:
Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
P = 10*log(Pout / Pin)
10 = 10*log(7/Pin)
1 = log(7/Pin)
10 = 7/Pin
10*Pin = 7
Pin = 7/10 = 0.7

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
P= 10 log Pout/Pin
where Pin is the power input in watts and Pout is the power output in watts. If an amplififier has a power gain of 10 watts and the output power is 7 watts, find the input power.
-----------
10 = 10 log (7/Pin)
divide both sides by 10 to get:
1=log(7/Pin)
Convert to exponential form to get:
7/Pin=10^1
Solve for Pin to get:
Pin=7/10
Power Input = (7/10) watt
Cheers,
Stan H.