Question 620474: i need help with this two part question we started slope and i am lost and getting frustrated. can someone help me step by step explain what you did.
1.The distance of the point (1,5) from the line y = -2 x - 1
is
2.The equation of the line that goes through the point ( 4 ,6 ) and is perpendicular to the line 4 x + 2 y = 3 can be written in the form y = mx+b where m is and b is
Found 4 solutions by ewatrrr, Alan3354, lynnlo, Edwin McCravy:
Answer by ewatrrr(24785)   (Show Source):
Answer by Alan3354(69443)  (Show Source):
You can put this solution on YOUR website! 1.The distance of the point (1,5) from the line y = -2x - 1
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This takes a few steps.
The distance is the minimum distance from the point to the line. That's the line perpendicular to the given line thru the point.
y = -2x - 1
Find the slope of y = -2x - 1
It's in slope-intercept form, y = mx + b, so the slope is -2.
The slope of lines perpendicular is the negative inverse, m = +1/2
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Now find the equation of the line with slope 1/2 that passes thru the point (1,5).
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Use y = mx + b and the point to find b, the y-intercept
5 = (1/2)*1 + b
b = 4.5
--> y = (1/2)x + 4.5 is the line thru (1,5) and perpendicular to y = -2x - 1
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Find the point of intersection of the 2 lines.
y = -2x - 1
y = x/2 + 4.5
Since they both = y:
-2x-1 = x/2 + 4.5
-4x-2 = x + 9
x = -11/5 or -2.2
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y = 3.4
--> point of intersection is (-2.2,3.4)
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Use the distance formula for the 2 points.
d =~ 3.5777 units.
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2.The equation of the line that goes through the point (4,6) and is perpendicular to the line 4x + 2y = 3 can be written in the form y = mx+b where m is and b is
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This is the same as the first part of #1.
Try it, email via the Thank You note for help or to check your work.
I'll bbl
Answer by lynnlo(4176)  (Show Source):
Answer by Edwin McCravy(20064)  (Show Source):
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