SOLUTION: The equation of the line that goes through the point ( 5, 5 ) and is parallel to the line going through the points ( -4 ,6 ) and ( 2 ,4 ) can be written in the form y = mx+b where

Algebra ->  Graphs -> SOLUTION: The equation of the line that goes through the point ( 5, 5 ) and is parallel to the line going through the points ( -4 ,6 ) and ( 2 ,4 ) can be written in the form y = mx+b where       Log On


   

Question 620465: The equation of the line that goes through the point ( 5, 5 ) and is parallel to the line going through the points ( -4 ,6 ) and ( 2 ,4 ) can be written in the form y = mx+b where m is and b is. I am struggling with this question i have no idea how to start this can you explain it in steps for me.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

The equation of the line that goes through the point ( 5, 5 ) 

and is parallel to the line going through the points 

( -4 ,6 ) and 

 ( 2 ,4 )  m = 2/-6 = (-1/3)

New Line:  (same slope)

 y = mx + b

 y = (-1/3)x + b     ||using Pt(5,5) to solve for b

5 = -5/3 + b

 20/3 = b

  y = (-1/3)x + 20/3