SOLUTION: what is the 6th term of (2x-1/3y)^7
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Question 620301
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what is the 6th term of (2x-1/3y)^7
Answer by
stanbon(75887)
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what is the 6th term of [(2x-(1/3)y)]^7
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6th term: 7C2*(2x)^2*(-(1/3)y)^5) = 21*4x^2*(-1/243)y^5
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= (-28/81)x^2y^5
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Cheers,
Stan H.