SOLUTION: Find 3 consecutive integers in which 3 times the sum of the first two is 16 more than the third.

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: Find 3 consecutive integers in which 3 times the sum of the first two is 16 more than the third.      Log On


   

Question 620251: Find 3 consecutive integers in which 3 times the sum of the first two is 16 more than the third.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
   

Hi,

Find 3 consecutive integers  highlight%28x%29,highlight%28x%2B1%29,highlight%28x%2B2%29   

in which 3 times the sum of the first two is 16 more than the third.

3[x + (x+1)] = (x+2)+16    ||Solve for x and other two consecutive integers