SOLUTION: if 6 is subtracted from the largest of three consecutive odd integers with the result multiplied by 2 the answer is 23 less than the sum of the first and twice the second of the in

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: if 6 is subtracted from the largest of three consecutive odd integers with the result multiplied by 2 the answer is 23 less than the sum of the first and twice the second of the in      Log On


   



Question 620118: if 6 is subtracted from the largest of three consecutive odd integers with the result multiplied by 2 the answer is 23 less than the sum of the first and twice the second of the integers. find the 3 integers
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let the 3 consecutive odd integers =
+n+, +n%2B2+, and +n+%2B+4+
+2%2A%28+n%2B+4+-+6+%29+=+n+%2B+2%2A%28+n+%2B+2+%29+-+23+
+2%2A%28+n+-+2+%29+=+n+%2B+2n+%2B+4+-+23+
+2n+-+4+=+3n+-+19+
+n+=+19+-+4+
+n+=+15+
+n+%2B+2+=+17+
+n+%2B+4+=+19+
The integers are 15, 17, and 19
check:
+2%2A%28+n%2B+4+-+6+%29+=+n+%2B+2%2A%28+n+%2B+2+%29+-+23+
+2%2A%28+19+-+6+%29+=+15+%2B+2%2A%28+17+%29+-+23+
+2%2A13+=+15+%2B+34+-+23+
+26+=+49+-+23+
+26+=+26+
OK