SOLUTION: Please help me solve this equation 2t2 – 19 – 6t

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Question 61998: Please help me solve this equation 2t2 – 19 – 6t
Answer by jai_kos(139) About Me  (Show Source):
You can put this solution on YOUR website!
2t^2 – 19 – 6t = 0
2t^2 -6t - 19 = 0 --->(1)

It is the quadratic equation of the form at^2+ bt + c = 0 --->(2)
When we compare the two equations we get,
a =2, b = -6, c = -19
We shall substitue in the quadratic formula, we get
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
x+=+%28-%28-6%29+%2B-+sqrt%28+%28-6%29%5E2-4%2A2%2A-19+%29%29%2F%282%2A2%29+
x+=+%28%2B6+%2B-+sqrt%28+36%2B152+%29%29%2F%284%29+
x+=+%28%2B6+%2B-+sqrt%28+188+%29%29%2F%284%29+
x+=+%28%2B6+%2B-+2sqrt%28+47+%29%29%2F%284%29+
x+=+%28%2B3+%2B-+sqrt%28+47+%29%29%2F%282%29+