SOLUTION: Jim started running track after school to get ready for basketball tryouts. The first day, he ran the quarter-mile track six times in 15 minutes. What was his rate of speed?
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Question 619867: Jim started running track after school to get ready for basketball tryouts. The first day, he ran the quarter-mile track six times in 15 minutes. What was his rate of speed? Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Jim started running track after school to get ready for basketball tryouts. The first day, he ran the quarter-mile track six times in 15 minutes. What was his rate of speed?
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Rate of speed?
It's either his rate, or his speed.
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d = 6 times 1/4 mile = 1.5 miles
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d = r*t
r = d/t = 1.5 mi/15 min
r = 0.1 mi/minute