SOLUTION: The length of a rectangle is 5 cm less than twice the width. Express as an integer the maximum width of the rectangle when the perimeter is less than 60 cm. I did 2w>5, but I don

Algebra ->  Inequalities -> SOLUTION: The length of a rectangle is 5 cm less than twice the width. Express as an integer the maximum width of the rectangle when the perimeter is less than 60 cm. I did 2w>5, but I don      Log On


   

Question 619820: The length of a rectangle is 5 cm less than twice the width. Express as an integer the maximum width of the rectangle when the perimeter is less than 60 cm.
I did 2w>5, but I don't understand what to do with the perimeter is less than 60.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

The length of a rectangle is 5 cm less than twice the width highlight%28x%29 . 

Express as an integer the maximum width of the rectangle when the perimeter is less than 60 cm. 

 P = 2W + 2L = 2x + 2(2x-5)< 80

               2x + 2(2x-5)< 80

               6x < 90

                x < 15

CHECKING our Answer*** trying x = 14

2· 14 + 2(28-5) =  28 + 46 =  74 < 80