Question 619771: A teller gave a customer change for $500 bills in $5, $10,$20 bills. Three are twice as much
10 bills as $20 bills altogether there are 40 bills. How much of each bill did the customer get
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! A teller gave a customer change for $500 bills in $5, $10,$20 bills.
There are twice as much 10 bills as $20 bills
altogether there are 40 bills.
How much of each bill did the customer get
:
Let x = no. of $5
Let y = no. of $10
Let z = no. of $20
:
"There are twice as much 10 bills as $20 bills"
y = 2z
:
"altogether there are 40 bills."
x + y + z = 40
and the total value equation
5x + 10y + 20z = $500
Replace y with 2z
5x + 10(2z) + 20z = 500
5x + 20z + 20z = 500
5x + 40z = 500
simplify, divide by 5
x + 8z = 100
x = (100-8z)
:
The total bill equation, replace x with (100-8z) and y with 2z
(100-8z) + 2z + z = 40
-5z = 40 - 100
-5z = -60
z = -60/-5
z = 12 ea 20 dollar bills
Find y
y = 2(12)
y = 24 ea $10 bills
Find x
x = 100 - 8(12)
x = 100 - 96
x = 4 ea $5 bills
:
:
Confirm this, find the total$
4(5) + 24(10) + 12(20) =
20 + 240 + 240 = 500
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