SOLUTION: Find exact solutions over the indicated intervals (x real and theta in degrees) 2sin^2theta+ 5sin theta-3=0, 0 degrees in less than or equal to theta less than 360 degrees

Algebra ->  Trigonometry-basics -> SOLUTION: Find exact solutions over the indicated intervals (x real and theta in degrees) 2sin^2theta+ 5sin theta-3=0, 0 degrees in less than or equal to theta less than 360 degrees      Log On


   



Question 619473: Find exact solutions over the indicated intervals (x real and theta in degrees)
2sin^2theta+ 5sin theta-3=0, 0 degrees in less than or equal to theta less than 360 degrees

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Find exact solutions over the indicated intervals (x real and theta in degrees)
2sin^2theta+ 5sin theta-3=0, 0 degrees in less than or equal to theta less than 360 degrees
**
2sinx+5sinx-3=0
(2sinx-1)(sinx+3)=0
sinx+3=0
sinx=-3 (reject, -1 ≤ x ≤ 1)
2sinx-1
sinx=1/2
x=30º and 150º