SOLUTION: The sum of 3 times a number and twice another number is 120. Twice the first number plus 4 times other number is 64. Calculate both numbers
2. The sum of 2 numbers is 64 and 3
Question 619419: The sum of 3 times a number and twice another number is 120. Twice the first number plus 4 times other number is 64. Calculate both numbers
2. The sum of 2 numbers is 64 and 3 times the difference is 30. Answer by ewatrrr(24785) (Show Source):
Hi,
The sum of 3 times a number and twice another numberis 120.
Twice the first numberplus 4 times other numberis 64.
3x +2y = 120
2x +4y = 64
The sum of 2 numbers is 64 and 3 times the difference is 30.
x + y = 64
3x-3y = 30
3x + 3y = 192 |multiplying 1st EQ thru by 3 to eliminate the y variable
3x -3y = 30
6x = 222
x = 37 and y = 27