SOLUTION: Solve the logarithmic equation: log(x+1)+log(x-1)=log3
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Question 619317
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Solve the logarithmic equation: log(x+1)+log(x-1)=log3
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sophxmai(62)
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Using the rule loga+logb=logab
log(x+1)+log(x-1)=log3
log[(x+1)*(x-1)]=log3
log(x^2-x+x-1)=log3
log(x^2-1)=log3
10^[log(x^2-1)]=10^log3
x^2-1=3
x^2=4
x=sqrt4
x=+2,-2