SOLUTION: please help me solve this problem : the length of a rectangle is 4 ft longer than twice the width. If the perimeter is 74 ft. find the length and the width
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Question 619279: please help me solve this problem : the length of a rectangle is 4 ft longer than twice the width. If the perimeter is 74 ft. find the length and the width Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! the length of a rectangle is 4 ft longer than twice the width. If the perimeter is 74 ft. find the length and the width
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Let width be "x"
Then length is "2x+4"
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Equation:
P = 2(L + W)
74 = 2(2x+4 + x)
37 = 3x+4
3x = 33
x = 11 ft (width)
2x+4 = 26 ft (length)
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Cheers,
Stan H.
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