SOLUTION: show the work to solve for L (liters): r = 2/((5L)^-1/2)

Algebra ->  Exponents-negative-and-fractional -> SOLUTION: show the work to solve for L (liters): r = 2/((5L)^-1/2)      Log On


   

Question 619277: show the work to solve for L (liters):
r = 2/((5L)^-1/2)
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
solve for L (liters):
r = 2/((5L)^-1/2)
------
r = 2*(5L)^(1/2)
(5L)^(1/2) = r/2
---
Square both sides:
5L = r^2/4
----
L = r^2/20
-----------------
Cheers,
Stan H.