Question 619126: A softball is thrown up into the air. The ball's height in feet is modeled by the equation h(t) = -16t2 + 32t + 5.
h = height
t = time in seconds
Find the maximum height of the ball.
a) 7.6 feet
b) 13.9 feet
c) 8.3 feet
d) 12.2 feet
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! A softball is thrown up into the air. The ball's height in feet is modeled by the equation h(t) =
-16t2 + 32t + 5.
Find its maximum height
**
This is just an equation of a parabola that opens downwards, so it has a maximum.
To find the maximum put equation into standard form: y=-A(x-h)^2+k, (h,k)=(x,y) coordinates of the vertex. k or the y-coordinate of the vertex is the maximum height.
..
y= -16t^2 + 32t + 5.
Complete the square
y= -16(t^2 -2t+1) + 5+16
y=-16(t-1)^2+21
ans:
maximum height of the ball=21 ft
none of your answers are correct
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