SOLUTION: x^2+8x+20=0 i dont know if these are complex numbers but the problem says solve the equation in the complex number system

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Question 619026: x^2+8x+20=0
i dont know if these are complex numbers but the problem says solve the equation in the complex number system

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


ALL numbers are in the complex number system. Real numbers just happen to have an imaginary part coefficient of zero.

Use the discriminant to determine the nature of your roots:

For any quadratic polynomial equation of the form:



Find the Discriminant, and evaluate the nature of the roots as follows:

No calculation quick look: If the signs on and are opposite, then guaranteed.

Two real and unequal roots. If is a perfect square, the quadratic factors over (the rationals).

One real root with a multiplicity of two. That is to say that the trinomial is a perfect square and has two identical factors. Presuming rational coefficients, the root will be rational as well.

A conjugate pair of complex roots of the form where is the imaginary number defined by

For your problem, 64 - 80 = -16, so

Go right from here to the quadratic formula:

From here just simplify. Your two zeros will have the form

John

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