SOLUTION: Divide 32 into two parts such that five times of the first part exceeds four times of the second part by twenty five.

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Question 618933: Divide 32 into two parts such that five times of the first part exceeds four times of the second part by twenty five.
Answer by Maths68(1474) About Me  (Show Source):
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Let x be the first part
Then Second part will be = 32-x
Five times of the first part exceeds four times of the second part by twenty five
5x=4(32-x)+25
5x=128-4x+25
5x=153-4x
5x+4x=153
9x=153
9x/9=153/9
x=17
First Part = 17
Second Part = 32-17=15

Check
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5 times of first part = 5(17)=85
4 times of second part = 4(15)=60
5times of first=4times of the second part + 25
85=60+25
85=85