SOLUTION: I need someone to show me how to graph this . write the equation of the line with slope-1/2 and -y intercept(0,3) then graph I worked it out 2y=-x+6 y=3 slope -1/2 I am not sure i

Algebra ->  Coordinate-system -> SOLUTION: I need someone to show me how to graph this . write the equation of the line with slope-1/2 and -y intercept(0,3) then graph I worked it out 2y=-x+6 y=3 slope -1/2 I am not sure i      Log On


   

Question 61885: I need someone to show me how to graph this . write the equation of the line with slope-1/2 and -y intercept(0,3) then graph
I worked it out 2y=-x+6 y=3 slope -1/2 I am not sure if that is correct and I do not know how to graph it.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
write the equation of the line with slope-1/2 and -y intercept(0,3) then graph
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The slope-intercept form of the line is y=mx+b
You are told the slope is 1/2 and the y-intercept is 3
So, the equation is y=(1/2)x+3
To graph you could find the x-intercept:
Let y=0, then 0=(1/2)x+3
(1/2)x=-3
x=-6
You now have two points: (0,3) and (-6,0)
Plot those two points and draw a line thru
them. That is your graph.
graph%28300%2C200%2C-10%2C10%2C-10%2C10%2C%281%2F2%29x%2B3%29
Cheers,
Stan H.