SOLUTION: Can u solve these problems by steps? 1 3/2x+4=-9 3/2x=-9-4 2 2(3x-7)+4x=26 3 4-3x=5-6x-7 8 solve the equations : y=2x+5 and 3x-2y=10 9 solve the equations

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Can u solve these problems by steps? 1 3/2x+4=-9 3/2x=-9-4 2 2(3x-7)+4x=26 3 4-3x=5-6x-7 8 solve the equations : y=2x+5 and 3x-2y=10 9 solve the equations       Log On


   

Question 6187: Can u solve these problems by steps?
1 3/2x+4=-9
3/2x=-9-4

2 2(3x-7)+4x=26
3 4-3x=5-6x-7
8 solve the equations : y=2x+5 and 3x-2y=10
9 solve the equations : 6x-3y=11 and 6x+3y=17
10 solve the equations 3x+5y=22 and 4x+3y=11
Found 2 solutions by hamda, bijar:
Answer by hamda(7) About Me  (Show Source):
You can put this solution on YOUR website!
1 3/2x+4=-9
3/2x=-9-4
3/2x=-13
3=-13(2x)
3=-26x
x=-3/26

2 2(3x-7)+4x=26
6x-14+4x=26
10x=26+14
10x=40
x=40/10
x=4
3 4-3x=5-6x-7
4-3x=-2-6x
4+2=3x-6x
6=-3x
x=6/-3
x=-2
8 solve the equations : y=2x+5 and 3x-2y=10
y=2x+5 ---- eq.1
3x-2y=10 -----eq.2
Substituting 'y' from equation 1 in equation 2:
3x-2(2x+5)=10
3x-4x-10=10
-x-10=10
x=-10-10
x=-20

Substituting 'x' in equation 1:
y=2(-20)+5
y=-40+5
y=-35

9 solve the equations : 6x-3y=11 and 6x+3y=17
6x-3y=11 ---- eq.1
6x+3y=17 ---- eq.2
Solving by elimination method:
12x=28
x=28/12
x=7/3

Substituing 'x' in equation 1:
6(7/3)-3y=11
14-3y=11
y=1
10 solve the equations 3x+5y=22 and 4x+3y=11
3x+5y=22 ---- eq.1
4x+3y=11 ---- eq.2

From eq. 1:
x=(22-5y)/3 ----eq.3

Substituing 'x' in equation 2:
4((22-5y)/3)+3y=11
(88-20y)/3 +3y=11
88-20y+9y=33
-11y=-55
y=5
Substituing 'y' in equation 3:
x=(22-5(5))/3
x=(22-25)/3
x=-3/3
x=-1

Answer by bijar(1) About Me  (Show Source):
You can put this solution on YOUR website!
1 3/2x+4=9
3/2x=-9-4
3/2x=-13

we use the algebric rule of changing the sides,
-3/13=2x


-3/26=x answer


2 2(3x-7)+4x=26
6x-14+4x=26
10x=26+14
10x=40
x=40/10
x=4 answer


3 4-3x=5-6x-7
4-3x=-2-6x
4+2=-6x+3x
6=-3x
-6/3=x
x=-2 answer


8 y=2x+5 and 3x-2y=10
let y=2x+5 be equation 1
let 3x-2y=10 be equation 2

substitute equation 1 into equation 2
3x-2(2x+5)=10
now , we will multiply -2 by (2x+5)

3x-4x-10=10
-x=10+10
-x=20 y=2(-20)+5
y=-40+5
y=-35
x=-20 answer






9 6x-3y=11 and 6x+3y=17
let 6x-3y=11 be equation 1 and 6x+3y=17 be equation 2

solving equation 1 , 6x-11=3y
6x/3 -11/3=y
2x-11/3=y


6x+3(2x-11/3)=17 y=2(7/3)-11/3
y=14/3-11/3
y=3/3 , y=1
6x+6x-11=17
12x=28
x=28/12
x=7/3 answer




10 3x+5y=22 is equation 1
4x+3y=11 is equation 2

solve equation 1
3x=22-5y
x=22/3-5y/3
substitute in equation 2.

4(22/3-5y/3)+3y=11
88/3-20y/3+3y=11
-20y+9y =3(11-88/3)
-11y=3(-55/3)
-11y=-55 both minus signs are cancelled
11y=55
y=5

3x+5y=22
3x+5(5)=22
3x=22-25
3x=-3
x=-1