Determine whether each of the distributions given below represents a probability distribution.    Justify your answer. 
All the probabilities must be
1. All probabilities between 0 and 1 inclusive.  
2. The sum of all the probabilities must
equal exactly 1
(A)  
 x    P(x)
 1    1/4
 2    5/12
 3    1/3
 4    1/6
 
1.  All those probabilities are between 0 and 1.
2.  The sum of the probabilities is
     +
+ +
+ +
+ =
    Get an LCD of 12:
=
    Get an LCD of 12:
     +
+ +
+ +
+ =
=
     =
 =  =
 =  No, that sum is not 1, so it is NOT a
    probability distribution  
(B) 
 x   P(x)
 3    0.1
 6    3/5
 8    0.3
 
1. All those probabilities are between 0 and 1.
2. The sum of the probabilities is
   0.1+
    No, that sum is not 1, so it is NOT a
    probability distribution  
(B) 
 x   P(x)
 3    0.1
 6    3/5
 8    0.3
 
1. All those probabilities are between 0 and 1.
2. The sum of the probabilities is
   0.1+ +0.3 = 0.1+0.6+0.3 = 1.0
   Yes, that sum is 1, so it IS a probability
   distribution. 
(C) 
 x   P(x)
20    0.2
30   -0.2
40    0.7
50    0.3
 1.  That second probability is negative, and
     so it is not a probability distribution.   
 2.  The sum of the probabilities is 1, but
     that does not matter. No probability is
     ever negative.  So it is NOT a probability
     distribution.
Edwin
+0.3 = 0.1+0.6+0.3 = 1.0
   Yes, that sum is 1, so it IS a probability
   distribution. 
(C) 
 x   P(x)
20    0.2
30   -0.2
40    0.7
50    0.3
 1.  That second probability is negative, and
     so it is not a probability distribution.   
 2.  The sum of the probabilities is 1, but
     that does not matter. No probability is
     ever negative.  So it is NOT a probability
     distribution.
Edwin