SOLUTION: How do you solve this problem by substitution or elimination? (Your choice)
x^2+y^2+2x+2y=0
x^2+y^2-2x-2y=0
Algebra ->
Systems-of-equations
-> SOLUTION: How do you solve this problem by substitution or elimination? (Your choice)
x^2+y^2+2x+2y=0
x^2+y^2-2x-2y=0
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You can put this solution on YOUR website! x^2+y^2 +2x +2y =0
so using substitution method:
x^2 +y^2 = -2x -2y
(-2x -2y) -2x -2y = 0
-4x - 4y = 0
-4x = 4y
x = -y or y=-x
Sub y=-x in for either equation.
x^2 + (-x)^2 -2x + 2x = 0
2x^2 = 0
x = 0 <--------
x =-y
0 =-y
y=0 <------
If you want to visualize this, you have two circles that intersect at (0,0).
