SOLUTION: The ages of three siblings are consecutive odd integers. The difference in the ages between three times the age of the younger child and the age of the middle child is one more tha

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Question 618451: The ages of three siblings are consecutive odd integers. The difference in the ages between three times the age of the younger child and the age of the middle child is one more than the age of the oldest. How old is the oldest child?
a. 7 years
b. 9 years
c. 11 years
d. 13 years
Found 2 solutions by stanbon, richwmiller:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
The ages of three siblings are consecutive odd integers. The difference in the ages between three times the age of the younger child and the age of the middle child is one more than the age of the oldest. How old is the oldest child?
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1st: 2x-1
2nd: 2x+1
3rd: 2x+3
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Equation:
3(2x-1)-(2x+1) = 2x+3 + 1
------
6x-3-2x-1 = 2x+4
4x-4 2x+4
2x = 8
x = 4
oldest = 2x+3 = 8+3 = 11 yrs.
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Cheers,
Stan H.
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a. 7 years
b. 9 yeard
c. 11 years
d. 13 years

Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!

3x-(x+2)=x+4+1
2x-2=x+5
x=7 youngest
x+2=9 middle
x+4=11 oldest
c) 11 years