SOLUTION: divide (30b^3+13b^2+44b+46b)/(6b+5)

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: divide (30b^3+13b^2+44b+46b)/(6b+5)      Log On


   

Question 618338: divide (30b^3+13b^2+44b+46b)/(6b+5)
Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
I'm assuming that the last term in the numerator is just 46, not 46b...
%2830b%5E3%2B13b%5E2%2B44b%2B46%29%2F%286b%2B5%29
Using long division:
       5b^2 + (-2b) +     9
     ___________________________
6b+5/ 30b^3 + 13b^2 +   44b + 46
      30b^2 + 25b^2
      =============
             -12b^2 +   44b
             -12b^2 + (-10b)
             ===============
                        54b + 46
                        54b + 45
                        ========
                               1

So


P.S. If the last term of the numerator was 45, then there would be no remainder and the answer would just be 5b%5E2+%2B+%28-2b%29+%2B+++++9