SOLUTION: What is log(base3)8+log(base3)(7-2x)=2

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Question 618297: What is log(base3)8+log(base3)(7-2x)=2
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
log(base3)8+log(base3)(7-2x)=2
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log%283%2C8%29+%2B+log%283%2C7-2x%29+=+2
log%283%2C8%287-2x%29%29+=+2
8%287-2x%29+=+8%5E2
56-16x+=+64+
-16x+=+8+
x+=+8%2F%28-16%29+
x+=+1%2F%28-2%29+
x+=+-1%2F2+