Question 618274: Determine an equation for the line perpendicular to 5x+9y=-8 and passing through the point (-10,-9).
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Determine an equation for the line perpendicular to 5x+9y=-8 and passing through the point (-10,-9).
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Equation for a straight line: y=mx+b, m=slope, b=y-intercept
Equation of given line:
5x+9y=-8
9y=-5x-8
y=-5x/9-8/9
slope=-5/9
..
slope of line perpendicular to given line=9/5 (negative reciprocal)
equation: y=9x/5+b
solving for b using coordinates of given point (-10,-9)
-9=(9*-10)/5+b
-9=-18+b
b=9
equation of perpendicular line: y=9x/5+9
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