You can put this solution on YOUR website! Please help me find the Domain of p(x)= 2x+1/6x^2+3x-30
PLEASE USE BRACKETS PROPERLY..DO YOU MEAN..
P(X)=[2X]+[1/6X^2]+[3X-30]...IF SO THERE IS ONLY ONE CRITICAL TERM WHICH COULD
MAKE THE FUNCTION UNDEFINED..IT IS 1/6X^2...IT IS NOT DEFINED FOR X=0
HENCE DOMAIN IS ALL REAL VALUES EXCEPT ZERO.
IF YOU MEANT
P(X) = 2X+[1/(6X^2+3X-30)]..THEN THE CRITICAL TERM IS
1/(6X^2+3X-30)= 1/[3(2X^2+X-10)] =1/[3(X-2)(2X+5)]
SO THE FUNCTION IS UNDEFINED AT X=2 AND -5/2
HENCE DOMAIN IS ALL REAL NUMBERS EXCEPT 2 AND -5/2...THAT IS
(-INFINITY,-5/2)U(-5/2,2)U(2,+INFINITY)