SOLUTION: The diameters of grapefruits in a certain orchard are normally distributed with a mean of 6.95 inches and a standard deviation of 0.75 inches. Show all work.
(A) What percentag
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-> SOLUTION: The diameters of grapefruits in a certain orchard are normally distributed with a mean of 6.95 inches and a standard deviation of 0.75 inches. Show all work.
(A) What percentag
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Question 618180: The diameters of grapefruits in a certain orchard are normally distributed with a mean of 6.95 inches and a standard deviation of 0.75 inches. Show all work.
(A) What percentage of the grapefruits in this orchard have diameters less than 6.6 inches?
(B) What percentage of the grapefruits in this orchard are larger than 6.9 inches? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! The diameters of grapefruits in a certain orchard are normally distributed with a mean of 6.95 inches and a standard deviation of 0.75 inches. Show all work.
(A) What percentage of the grapefruits in this orchard have diameters less than 6.6 inches?
z(6.6) = (6.6-6.95)/0.75 = -0.4667
P(x < 6.6) = P(z < -0.4667) = 0.3204 = 32.04%
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(B) What percentage of the grapefruits in this orchard are larger than 6.9 inches?
Do the same with 6.9.
Find its z-score
Find the probability z igreater than that z-score.
I get answer = 0.5266 = 53.66%
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Cheers,
Stan H.
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