SOLUTION: Suppose we want to determine the (binomial) probability(p) of getting 5 heads in 11 flips of a 2-sided coin. Using the Binomial Probabilities Table in Appendix B of the text, wha

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: Suppose we want to determine the (binomial) probability(p) of getting 5 heads in 11 flips of a 2-sided coin. Using the Binomial Probabilities Table in Appendix B of the text, wha      Log On


   

Question 617935: Suppose we want to determine the (binomial) probability(p) of getting 5 heads in 11 flips of a 2-sided coin. Using the Binomial Probabilities Table in Appendix B of the text, what values of n, x and p would we use to look up this probability, and what would be the probability?
Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
the value of n would be 11
the value of x would be 5
the value of p would be .5
the value of q = 1-p would also be .5
the formula is:
nCx*p^x*q^(n-x)
you should get:
11C5*.5^5*.5^6 equals .225585938
11C5 is equivalent to 11! / (5!*6!) which is equal to 462
.5^5 is equal to .03125
.5^6 is equal to .015625
all of the probabilities are shown in the following table.
the sum of the probabilities should be equal to 1 as shown.
n	x	nCx	(.5)^x	        (.5)^(n-x)	nCx*(.5)^x*(.5)^(n-x)

11	0	1	1	        0.000488281	0.000488281
11	1	11	0.5	        0.000976563	0.005371094
11	2	55	0.25	        0.001953125	0.026855469
11	3	165	0.125	        0.00390625	0.080566406
11	4	330	0.0625	        0.0078125	0.161132813
11	5	462	0.03125	        0.015625	0.225585938 *****
11	6	462	0.015625	0.03125	        0.225585938
11	7	330	0.0078125	0.0625	        0.161132813
11	8	165	0.00390625	0.125	        0.080566406
11	9	55	0.001953125	0.25	        0.026855469
11	10	11	0.000976563	0.5	        0.005371094
11	11	1	0.000488281	1	        0.000488281
				total probability >>>>>	1