SOLUTION: Factor completely 2x^2 – 20x -50

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Question 617823: Factor completely 2x^2 – 20x -50

Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
2*(x^2-10x-25)
find factors of -50 which add up to -10
Solved by pluggable solver: Factoring using the AC method (Factor by Grouping)


Looking at the expression x%5E2-10x-25, we can see that the first coefficient is 1, the second coefficient is -10, and the last term is -25.



Now multiply the first coefficient 1 by the last term -25 to get %281%29%28-25%29=-25.



Now the question is: what two whole numbers multiply to -25 (the previous product) and add to the second coefficient -10?



To find these two numbers, we need to list all of the factors of -25 (the previous product).



Factors of -25:

1,5,25

-1,-5,-25



Note: list the negative of each factor. This will allow us to find all possible combinations.



These factors pair up and multiply to -25.

1*(-25) = -25
5*(-5) = -25
(-1)*(25) = -25
(-5)*(5) = -25


Now let's add up each pair of factors to see if one pair adds to the middle coefficient -10:



First NumberSecond NumberSum
1-251+(-25)=-24
5-55+(-5)=0
-125-1+25=24
-55-5+5=0




From the table, we can see that there are no pairs of numbers which add to -10. So x%5E2-10x-25 cannot be factored.



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Answer:



So x%5E2-10%2Ax-25 doesn't factor at all (over the rational numbers).



So x%5E2-10%2Ax-25 is prime.