|
Question 617756: How would you answer:
Write the equation of the line containing the points of (-1,-2) and (-2,-4).
How would you answer:
Write the equation of the line perpendicular to 3y-2x-5=0 containing the point (-4,5).
I have a FINAL EXAM tomorrow and I need at least a 90 on it.
Answer by scott8148(6628)   (Show Source):
You can put this solution on YOUR website! first find the slope ___ m = (-4 - -2) / (-2 - -1) = -2 / -1 = 2
use the slope-intercept equation ___ y = mx + b
___ put in the slope, then use one of the given points to find the intercept (b)
___ y = 2x + b ___ (-2) = 2(-1) + b ___ -2 = -2 + b ___ 0 = b
___ so the equation is ___ y = 2x
start the same way, by finding the slope; solving for y to get the slope intercept form
3y = 2x + 5 ___ y = (2/3)x + (5/3)
the slope of the perpendicular is the negative reciprocal ___ y = (-3/2)x + b
again, use the given point to find b ___ (5) = (-3/2)(-4) + b ___ 5 = 6 + b ___ -1 = b
___ so the equation is ___ y = (-3/2)x - 1
good luck on the exam
|
|
|
| |
