You can put this solution on YOUR website! how many liters of water must be added to 35 liter of 89%hydrochloric acid solution to reduce its strength to 75%?
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Let w = amt of water to accomplish this
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A simple "amt of acid equation" (amt of acid remains the same, only the Percent changes)
.89(35) = .75(w+35)
31.15 = .75w + 26.25
31.15 - 26.25 = .75w
4.9 = .75w
w = 4.9/.75
w = 6.533 liter of water