SOLUTION: Find the set of all complex solutions. {{{x^3}}}+6x={{{2x^2}}}+12

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Question 61753: Find the set of all complex solutions.
x%5E3+6x=2x%5E2+12
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
x^3+6x=2x^2+12
x^3-2x^2+6x-12=0
x=2 is a zero
Divide by (x-2) to get:
x^2+6
Zeroes of this are x=isqrt6 or x=-isqrt6
Cheers,
Stan H.