SOLUTION: Hi, I need some help with this problem.It says solve the equation and assume the replacement set is the set of real numbers. a) 4[6x-5(x-3)]= 10x+24 I tried: 4[6x-5x+15

Algebra ->  Test -> SOLUTION: Hi, I need some help with this problem.It says solve the equation and assume the replacement set is the set of real numbers. a) 4[6x-5(x-3)]= 10x+24 I tried: 4[6x-5x+15      Log On


   



Question 617523: Hi, I need some help with this problem.It says solve the equation and assume the replacement set is the set of real numbers.
a) 4[6x-5(x-3)]= 10x+24
I tried:
4[6x-5x+15]= 10x+24
24x-20x+60=10x+24
4x+60=10x+24
solve for x and I get 2.57
I know is no right.Ineed some advice please

an the I have
b) x/4-1/8=3/8-x/2 Idon't know where to start.
Thanks.

Answer by lynnlo(4176) About Me  (Show Source):
You can put this solution on YOUR website!
(a)x=6
(b)x=2/3