SOLUTION: I need to do an equation, 4/3(5-2)=7[x-(5x-2)]. I think the problem I am having is with multiplying the 4/3(5-2). I have tried it and came out with the wrong answer 3 times. The

Algebra ->  Linear-equations -> SOLUTION: I need to do an equation, 4/3(5-2)=7[x-(5x-2)]. I think the problem I am having is with multiplying the 4/3(5-2). I have tried it and came out with the wrong answer 3 times. The      Log On


   



Question 617504: I need to do an equation, 4/3(5-2)=7[x-(5x-2)]. I think the problem I am having is with multiplying the 4/3(5-2). I have tried it and came out with the wrong answer 3 times. The answer is 25/52
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
4/3(5-2)=7[x-(5x-2)]
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(4/3)(3) = 7[x-5x+2]
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4 = 7[-4x+2]
4 = -28x + 14
28x = 10
x = 5/14
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Cheers,
Stan H.
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