SOLUTION: This is pertaining to the problem from Question 5039. Here is the problem: please help me answer and show me the work steps to this question. the cube of a number equals nine ti

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: This is pertaining to the problem from Question 5039. Here is the problem: please help me answer and show me the work steps to this question. the cube of a number equals nine ti      Log On


   



Question 6175: This is pertaining to the problem from Question 5039.
Here is the problem:
please help me answer and show me the work steps to this question.
the cube of a number equals nine times the number.what is the number
Answer by Earlsdon(87) (Show Source):
Let n = the number.
n^3 = 9n Divide both sides by n
n^2 = 9 Take the square root of both sides.
n = +/- 3
Both 3 and -3 will work here.

My question is, where does the n^2 come from? Will you please show each step taken to solve this problem?
Thanks,
TSJ

Answer by guapa(62) About Me  (Show Source):
You can put this solution on YOUR website!
(((n^3=9n}}}
You divide both sides by n
n%5E3%2Fn=9n%2Fn The property for diving exponents is b%5En%2Fb%5Em=b%5E%28n-m%29
n has an exponent of 1 = (n%5E1)
Thus you get n%5E2=9
Hope this helps