SOLUTION: Two joggers set out at the same time from their homes 30 miles apart. They agree to meet at a point somewhere in between in two and a half hours. If the rate of one is 2 mph faster
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Question 617499: Two joggers set out at the same time from their homes 30 miles apart. They agree to meet at a point somewhere in between in two and a half hours. If the rate of one is 2 mph faster than the rate of the other, find the rate of each Found 2 solutions by josmiceli, ankor@dixie-net.com:Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! Let = the speed of the slower jogger in mi/hr = the speed of the faster jogger in mi/hr
Let = the distance the slower jogger has to
run until they meet = the distance the faster jogger runs
-----------------
Equation for slower jogger:
(1)
Equation for faster jogger:
(2)
-------------------------------
Substitute (1) into (2)
(2)
(2)
(2)
(2)
(2)
and
5 mi/hr is the speed of the slower jogger
7 mi/hr is the speed of the faster jogger
check:
(2)
(2)
(2)
(2)
and
(1)
(1)
(1)
OK
You can put this solution on YOUR website! Two joggers set out at the same time from their homes 30 miles apart.
They agree to meet at a point somewhere in between in two and a half hours.
If the rate of one is 2 mph faster than the rate of the other, find the rate of each
:
let r = rate of the slower jogger
then
(r+2) = rate of the faster
:
Write a distance equation, dist = time * rate
2.5r + 2.5(r+2) = 30
2.5r + 2.5r + 5 = 30
5r = 30 - 5
5r = 25
r = 25/5
r = 5 mph is the slower jogger
and obviously
7 mph is the faster jogger
:
:
:
Check the total distance, to confirm our solutions
2.5(5) + 2.5(7) =
12.5 + 17.5 = 30